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Find the sum of the infinite geometric series 8 + 4 + 2 + 1 +...
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Rule \[\Large \sum_{k=1}^{\infty}a*r^{k-1} = \frac{a}{1-r}\] if and only if |r| < 1. Since r = 0.5, that makes |r| < 1 true, which allows us to use the formula
I'm confused, do I used that equation to find the sum? If so what is a?
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I posted what 'a' was in my second post above
a = first term
a = 8 is the first term r = 0.5 is the common ratio you use \[\Large S = \frac{a}{1-r}\]
So the sum is 16?
Yes.
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yep S = 16
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