Question

Brian has a bag that contains 14 red marbles and 12 yellow marbles. He selects a marble at random, and then, without replacing the first one, selects another marble at random.



What is the probability that Brian selects a red marble and then a yellow marble? Round your answer to the nearest percent.

Answer 1

@BrainSmart

Answer 2

@jabez177 @jim_thompson5910

Answer 3

@Whitemonsterbunny17 @geerky42

Answer 4

2/26 ?

Answer 5

I'm not too sure on this one...

Answer 6

can you tag some other peopl please, i tagged all the people that I know that are good in math.

Answer 7

Except one... @Pooja195 :P

Answer 8

Okay, thanks

Answer 9

@Black_ninja123

Answer 10

I had this question! O_O

Answer 11

Any answer choices?

Answer 12

nope

Answer 13

P(red and yellow) ≈ (blank space) %

Answer 14

\[P(R_1\cap Y_2)=P(Y_2|R_1)P(R_1)\]

Answer 15

?.?

Answer 16

what is that?

Answer 17

im not even that far in math to know that.. im in midddle schoool not high school..

Answer 18

P(red on first and yellow on second)=P(yellow on 2nd given red on first)*P(red on first)

Answer 19

The answer is 26% because 14/26*12/25=84/325
84/325 as a percent is 25.84%