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In a 45°-45°-90° triangle, the length of the hypotenuse is 11. Find the length of one of the legs.
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\[L=\frac{ 1 }{ 2 }H \sqrt{2}\]
A) \[11 \sqrt{3}\div 2\]
B) \[11\sqrt{2}\div 2\]
C) \[11 \sqrt{2}\]
You don't really need to put the choices out, just plug in the H of the formula i gave you and you'll be good...
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i dont have a calculator on me
You don't need one...
im not good with doing numbers in my head
H=Hypotenuse. So put the H in for the formula and tell me what you get
i know what H is
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wait so its C?
No
\[L=H \sqrt{2} \div 2\]
\[H=11\]
I hope you know that I'm just re-stating my first formula, re-arranged in a different way, right?
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