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Mathematics 4 Online
OpenStudy (theopenstudyowl):

I need some help with some Statistics calculator questions! Thankyou!

OpenStudy (theopenstudyowl):

OpenStudy (michele_laino):

I think it is 28.26 under the label "Coef"

OpenStudy (theopenstudyowl):

cool!

OpenStudy (michele_laino):

here you have this function: \[y = B + Ax\]

OpenStudy (theopenstudyowl):

ok

OpenStudy (michele_laino):

I say 28.3, which is the value of y when x=0

OpenStudy (theopenstudyowl):

ok that make sense!

OpenStudy (michele_laino):

I think y=28.26+0.486*x

OpenStudy (theopenstudyowl):

ok cool!

OpenStudy (michele_laino):

I think it is the subsequent ratio: \[\Large t = \frac{1}{{0.4865}}\]

OpenStudy (kyanthedoodle):

Why is the question post orange if you didn't summon me? This is weird O_O

OpenStudy (michele_laino):

namely the last option

OpenStudy (kyanthedoodle):

OOOOOOOOOHHHHH it's probably because of the whole QH thing.

OpenStudy (theopenstudyowl):

cool

OpenStudy (theopenstudyowl):

thnxs for explaining!

OpenStudy (michele_laino):

I see from your table that the requested value of p is p=0.168, under the label "p"

OpenStudy (michele_laino):

at first row

OpenStudy (theopenstudyowl):

ok cool sorry for the late reply

OpenStudy (theopenstudyowl):

bazinga

OpenStudy (michele_laino):

I think p=0.045 at first row, and last column, or "p" column, second table

OpenStudy (theopenstudyowl):

OpenStudy (michele_laino):

I think that we have to use: 30 -2 = 28 degrree of freedom, since we have two parameters, namelythe constants A and B which appears into this formula: y = Ax+B

OpenStudy (michele_laino):

sorry for my grammar errors

OpenStudy (theopenstudyowl):

OpenStudy (michele_laino):

I think it is 19.96

OpenStudy (michele_laino):

please wait

OpenStudy (michele_laino):

it is 0.2316, since the slope is 0.4865

OpenStudy (theopenstudyowl):

@Michele_Laino sorry for the lare reply, I am currently doing macro right now, here is ht enext question..

OpenStudy (michele_laino):

using the table of the "erf" function the requested value is: 1.96

OpenStudy (theopenstudyowl):

ok one more

OpenStudy (theopenstudyowl):

ty

OpenStudy (michele_laino):

here I use standard deviation = 0.2316 range of interval= 0.2316*1.96= 0.454 so my answer would be: 0.4865 +/- 0.454

OpenStudy (michele_laino):

such answer is not an option of yours!

OpenStudy (michele_laino):

try to ask to another QH

OpenStudy (theopenstudyowl):

still thinking lol?

OpenStudy (michele_laino):

@dan815 please help

OpenStudy (theopenstudyowl):

ok, what is your answer?

OpenStudy (michele_laino):

my answer is the first option, nevertheless I'm not able to justify it

OpenStudy (theopenstudyowl):

MINE 2, just checked my work

OpenStudy (theopenstudyowl):

@Michele_Laino can u answer some more???

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