I need some help with some Statistics calculator questions! Thankyou!
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OpenStudy (theopenstudyowl):
OpenStudy (michele_laino):
I think it is 28.26 under the label "Coef"
OpenStudy (theopenstudyowl):
cool!
OpenStudy (michele_laino):
here you have this function:
\[y = B + Ax\]
OpenStudy (theopenstudyowl):
ok
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OpenStudy (michele_laino):
I say 28.3, which is the value of y when x=0
OpenStudy (theopenstudyowl):
ok that make sense!
OpenStudy (michele_laino):
I think
y=28.26+0.486*x
OpenStudy (theopenstudyowl):
ok cool!
OpenStudy (michele_laino):
I think it is the subsequent ratio:
\[\Large t = \frac{1}{{0.4865}}\]
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OpenStudy (kyanthedoodle):
Why is the question post orange if you didn't summon me? This is weird O_O
OpenStudy (michele_laino):
namely the last option
OpenStudy (kyanthedoodle):
OOOOOOOOOHHHHH it's probably because of the whole QH thing.
OpenStudy (theopenstudyowl):
cool
OpenStudy (theopenstudyowl):
thnxs for explaining!
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OpenStudy (michele_laino):
I see from your table that the requested value of p is
p=0.168, under the label "p"
OpenStudy (michele_laino):
at first row
OpenStudy (theopenstudyowl):
ok cool sorry for the late reply
OpenStudy (theopenstudyowl):
bazinga
OpenStudy (michele_laino):
I think
p=0.045 at first row, and last column, or "p" column, second table
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OpenStudy (theopenstudyowl):
OpenStudy (michele_laino):
I think that we have to use:
30 -2 = 28 degrree of freedom, since we have two parameters, namelythe constants A and B which appears into this formula:
y = Ax+B
OpenStudy (michele_laino):
sorry for my grammar errors
OpenStudy (theopenstudyowl):
OpenStudy (michele_laino):
I think it is 19.96
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OpenStudy (michele_laino):
please wait
OpenStudy (michele_laino):
it is 0.2316, since the slope is 0.4865
OpenStudy (theopenstudyowl):
@Michele_Laino sorry for the lare reply, I am currently doing macro right now, here is ht enext question..
OpenStudy (michele_laino):
using the table of the "erf" function the requested value is: 1.96
OpenStudy (theopenstudyowl):
ok one more
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OpenStudy (theopenstudyowl):
ty
OpenStudy (michele_laino):
here I use standard deviation = 0.2316
range of interval= 0.2316*1.96= 0.454
so my answer would be:
0.4865 +/- 0.454
OpenStudy (michele_laino):
such answer is not an option of yours!
OpenStudy (michele_laino):
try to ask to another QH
OpenStudy (theopenstudyowl):
still thinking lol?
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OpenStudy (michele_laino):
@dan815 please help
OpenStudy (theopenstudyowl):
ok, what is your answer?
OpenStudy (michele_laino):
my answer is the first option, nevertheless I'm not able to justify it