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Mathematics 20 Online
OpenStudy (babynini):

Equation for lower half of parabola.

OpenStudy (babynini):

Find an eq for the lower half of the parabola, without restriction. (y-5)^2 = 4x-2

OpenStudy (hwyl):

it says for the lower half

zepdrix (zepdrix):

It's a parabola opening to the RIGHT, ya? So if you drew it, you would see that it `fails the vertical line test`. We want to show that either branch of the parabola IS a function. So we'll end up with y=(plus/minus) squareroot(x stuff) and to get the LOWER Half of the parabola, we want the negative of that root.

zepdrix (zepdrix):

Do you understand how to get it into the form y=stuff from what they've given you? :)

OpenStudy (babynini):

em i'm trying but i'm getting it wrong.

zepdrix (zepdrix):

You ... you and your ways miriam -_- ok let's see where we're going wrong,\[\Large\rm (y-5)^2 = 4x-2\]

zepdrix (zepdrix):

square root as first step, ya?

zepdrix (zepdrix):

\[\Large\rm y-5=\pm\sqrt{4x-2}\]Add some 5 business in there,\[\Large\rm y=\pm\sqrt{4x-2}+5\]

zepdrix (zepdrix):

We want the lower branch, ya? So we only want the negative root,\[\Large\rm y=-\sqrt{4x-2}+5\]

OpenStudy (babynini):

I was simplifying first and that was making it come out wrong

zepdrix (zepdrix):

|dw:1433476275143:dw|

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