someone please explain how to solve this Given ΔABC, m∠A = 60°, b = 9 and c = 6. Find m∠B. Round to the nearest whole degree. A) 8° B) 41° C) 71° D) 79°
do you know the law of sines?
its something like soh cah toa
you can only use that if you know it's a right triangle
it is soh cah toa
how about a/sinA=b/sinB=c/sinC
but which side is which
i dont know theres no picture
so try soh can toa, do you know what it stands for? *tip: c usually= hypotenuse
cah sorry not can
well then why is b bigger than c
@tlatti
no i dont understand th esoh cah toa i looked it up and i dont understand
Sine Opposite Hypotenuse Cosine Adjacent Hypotenuse Tangent Opposite Adjacent
|dw:1433517992401:dw|
you do not know that this is a right angle so you cannot use the standard trig functions
what im so confused
then what do i use
|dw:1433518102874:dw| the general triangle is drawn above
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