someone please explain how to solve this
Given ΔABC, m∠A = 60°, b = 9 and c = 6. Find m∠B. Round to the nearest whole degree.
A)
8°
B)
41°
C)
71°
D)
79°
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OpenStudy (anonymous):
do you know the law of sines?
OpenStudy (anonymous):
its something like soh cah toa
OpenStudy (anonymous):
you can only use that if you know it's a right triangle
OpenStudy (anonymous):
it is soh cah toa
OpenStudy (anonymous):
how about a/sinA=b/sinB=c/sinC
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OpenStudy (anonymous):
but which side is which
OpenStudy (anonymous):
i dont know theres no picture
OpenStudy (anonymous):
so try soh can toa, do you know what it stands for?
*tip: c usually= hypotenuse
OpenStudy (anonymous):
cah sorry not can
OpenStudy (anonymous):
well then why is b bigger than c
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OpenStudy (anonymous):
@tlatti
OpenStudy (anonymous):
no i dont understand th esoh cah toa i looked it up and i dont understand
OpenStudy (anonymous):
Sine
Opposite
Hypotenuse
Cosine
Adjacent
Hypotenuse
Tangent
Opposite
Adjacent
OpenStudy (anonymous):
|dw:1433517992401:dw|
OpenStudy (mrnood):
you do not know that this is a right angle so you cannot use the standard trig functions
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OpenStudy (anonymous):
what im so confused
OpenStudy (anonymous):
then what do i use
OpenStudy (mrnood):
|dw:1433518102874:dw|
the general triangle is drawn above