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Mathematics 21 Online
OpenStudy (anonymous):

help!!!! i will fan and medal!!!!!!!! http://uploadpie.com/8t7gK

OpenStudy (anonymous):

It's a right triangle, so you can use the pythagorean theorem.

OpenStudy (anonymous):

ohh ok ....so...then what?

OpenStudy (anonymous):

The equation is\[leg^2+leg^2=hypotenuse^2\]

OpenStudy (anonymous):

or\[14^2+x^2=20^2\]

OpenStudy (anonymous):

sooo....the answer is 34?

OpenStudy (anonymous):

No...how do you figure that?

OpenStudy (anonymous):

i added them

OpenStudy (anonymous):

XD

OpenStudy (anonymous):

\[x^2=20^2+14^2\] \[x^2=400-196\] \[x=\sqrt(204)\]

OpenStudy (anonymous):

204?

OpenStudy (anonymous):

i thought we were supose to add it?

OpenStudy (anonymous):

not quite, you need to use algebra to solve this one, you subtract 14^2 from both sides to get the variable on its own, then take the square root of the whole equation to get the final answer which is x=14.3

OpenStudy (anonymous):

OHH OK THANKS

OpenStudy (anonymous):

You're welcome!

OpenStudy (jack1):

nice work

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