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Mathematics 16 Online
OpenStudy (jravenv):

Help me with this?

OpenStudy (jravenv):

OpenStudy (sdfgsdfgs):

can u start by multiplying left and right hand side by 3? what will u get?

OpenStudy (jravenv):

9

OpenStudy (jravenv):

and I don't know who to do the other :/

OpenStudy (sdfgsdfgs):

Relax and let's work on it together okay? \[a = \frac{ x + y + z }{ 3 }\] multiplying left and right hand side by 3 - what will u get?

OpenStudy (jravenv):

Okay thanks, 3a+ x+y+z?

OpenStudy (sdfgsdfgs):

Almost...it should be: 3a = x + y + z u mixed up the "=" and "+" sign but its okay!

OpenStudy (jravenv):

Oh /.\ sorry! What do I do next?

OpenStudy (sdfgsdfgs):

subtract 3a from the left and right, now what u get?

OpenStudy (jravenv):

Um x+y+z-3a?

OpenStudy (sdfgsdfgs):

correct on the right hand side of the = sign....but how about the left hand side?

OpenStudy (jravenv):

-3a=x+y+z-3a?

OpenStudy (sdfgsdfgs):

The right hand side was 3a before...now subtracting 3a from that, what will u get?

OpenStudy (jravenv):

0!

OpenStudy (sdfgsdfgs):

Good job :) so we have 0 = x + y + z - 3a Now plz look at the choices in ur Q, what do u see?

OpenStudy (jravenv):

OpenStudy (anonymous):

not to butt in but your job is to solve for \(y\) not to set it equal to zero it takes two steps only

OpenStudy (sdfgsdfgs):

so y is by itself on one side right? that means u need to move everything else on the other side...

OpenStudy (sdfgsdfgs):

@satellite73 yes, sorry I realize...too late...that I should have kept 3a on the left....

OpenStudy (jravenv):

What do I do then?

OpenStudy (sdfgsdfgs):

take a step back... 3a = x + y + z now because as @satellite73 said, we need to solve for y. So we need to move x and z over to the left hand side. ok?

OpenStudy (jravenv):

Okay

OpenStudy (sdfgsdfgs):

We do that by subtracting x + y from the left and right hand side of the = sign what will be on the left?

OpenStudy (jravenv):

3a- x+y= z?

OpenStudy (sdfgsdfgs):

Yes and I made a mistake again :(

OpenStudy (sdfgsdfgs):

So it should look like this.... 3a - (x+z) = x + y + z - (x+z) so far so good?

OpenStudy (jravenv):

I think I figured it out, is it this? y = 3a - x - z

OpenStudy (sdfgsdfgs):

Bingo :) u got it!

OpenStudy (jravenv):

THANKS! YAY!

OpenStudy (sdfgsdfgs):

welcome!

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