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Mathematics 17 Online
OpenStudy (anonymous):

which of the following, if any, are polynomial functions?

OpenStudy (anonymous):

OpenStudy (anonymous):

yes second one is polynomial .

OpenStudy (anonymous):

not the first one because of the variable in the denominator

OpenStudy (anonymous):

you got that? no to the first yes to the second

OpenStudy (anonymous):

i dont think all polynomials are functions

OpenStudy (anonymous):

yes i understand that.. and just for educational purposes.. what makes something a polynomial function

OpenStudy (anonymous):

you have only positive integer exponents

OpenStudy (anonymous):

\[p(x)=a_nx^n+a_{n+1}x^{n-1}+...+a_1x+a_0\]

OpenStudy (anonymous):

yep satellite explained it

OpenStudy (anonymous):

alright and how would you determine the leading coefficient of a polynomial

OpenStudy (anonymous):

it is the coefficient of the term of highest degree (larges exponent)

OpenStudy (anonymous):

if the polynomial is written in standard form (from highest power to lowest) then it is the first coefficient you see

OpenStudy (anonymous):

\[f(x)=-4x^2+3x^2-5x+2\] leading coefficient is \(-4\) for example

OpenStudy (anonymous):

okay how about the polynomial: P(x)=3(x-1)(x+3)(2x-5)^2 would it be 3??

OpenStudy (anonymous):

no

OpenStudy (anonymous):

if you multiply out (in your head) you will get \(3\times4=12\)

OpenStudy (anonymous):

satellite the leading coefficient of -4 x^2 +3x^@-5x will be -1 ?

OpenStudy (anonymous):

or if you multiply out for real you get \[12 x^4-36 x^3-81 x^2+330 x-225\]but you don't need to do that to see the 12

OpenStudy (anonymous):

satellite reply my question i am asking u

OpenStudy (anonymous):

i don't understand it, look at what you wrote

OpenStudy (anonymous):

@chlobohoe do you see how i got the 12?

OpenStudy (anonymous):

yes i saw! cause you multiplied everything out. ima bout to post another question wait up<3

OpenStudy (anonymous):

will it be 1 ? http://prntscr.com/7dpfkw

OpenStudy (anonymous):

i mean -1

OpenStudy (anonymous):

lol i made a typo

OpenStudy (anonymous):

lol.its ok but u confused me :P

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