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Physics 20 Online
OpenStudy (anonymous):

Can someone PLEASE HELP ME OUT with capacitors in series?

OpenStudy (anonymous):

do you know @shaurya?

OpenStudy (anonymous):

when you add capacitors in series then they get added in the way resistances are added in parallel

OpenStudy (anonymous):

? If you connect 2 cables of 10μF in a total charge of 20V,whatI would be?

OpenStudy (anonymous):

yeah but idk what to do with that 10μF

OpenStudy (anonymous):

consider the two wires as capacitors each of 10uF

OpenStudy (anonymous):

sorry I really have no idea, we never used this unit before

OpenStudy (anonymous):

can you please help me out with this one?

OpenStudy (anonymous):

solve it as any other unit

OpenStudy (anonymous):

can you show me how to solve this one?

OpenStudy (anonymous):

or just from where to start?

OpenStudy (anonymous):

One farad is defined as the capacitance of a capacitor across which, when charged with one coulomb of electricity, there is a potential difference of one volt.

OpenStudy (anonymous):

so here it will be 20 volt, right?

OpenStudy (anonymous):

they ask me here what the voltage on each cable is

OpenStudy (anonymous):

in series 1/C equivalent = 1/c1 + 1/c2 so c equivalent will be 5 uF

OpenStudy (anonymous):

why?

OpenStudy (anonymous):

Vcx = Vs* (Ct/Cx) Where: CX is the capacitance of the capacitor in question, VS is the supply voltage across the series chain and VCX is the voltage drop across the target capacitor.

OpenStudy (anonymous):

its the formula

OpenStudy (anonymous):

if you are satisfied then give me a medal or say so

OpenStudy (anonymous):

thank you

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