How to factor 2x^2 - 1
its already factored .-.
Ok so 2x^2 - 1 has solutions 2x^2 = 1 2x^2 = 1/2 sqr(x^2) = sqr(1/2) ok I am stuck here to finding the solutions
Thats not right .-. if you were to sqrt the 2 and then you'd be left with \[(\sqrt{2}+1)(\sqrt{2}-1)\] diffrence of squares .-.
How do I get the solutions ?
Sqrt both numbers since its the difference of 2 squares ._.
a^2-b^2=(a+b)(a-b) a=sqrt(2)x b=1
Ah ok I see now. Thank you.
\[(\sqrt{2}x+1)(\sqrt{2}x−1)\]
im sorry i meant that ^
I got it. Thank you!
:) oh and this part too a^2-b^2 =\((\sqrt2 x)^2-1^2=2x^2-1\)
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