A figure shows a portion of a graph of f(x) = x^2 + 3x + 1 and a rectangle with its base on the x-axis and a vertex on the graph. what is the area of the rectangle? (hint: f(2) is the height) ???

Question

anonymous · Answer

hmm, how do you find the rectangles width?

anonymous · Answer

This is all that it says, problem #70

anonymous · Answer

$f(0.2)$ is the height, not $f(2)$.

The width of the rectangle is the difference between the interval's endpoints: $0.3-0.2=0.1$. So, the area of the rectangle is $0.1\times f(0.2)$.