Question

HELP please :c
What are the possible numbers of positive, negative, and complex zeros of f(x) = -x^6 + x^5- x4 + 4x^3 - 12x^2 + 12?.... O.o

Answer 1

So for finding the number of possible positive zeros, we simply count the amount of times the terms change signs as we look at each one.

So the first term is negative and the 2nd is positive. That's one sign change.
Then the next term is negative, another sign change
The next term is positive, a 3rd sign change.
In the end, we changed sign 5 times, so there are 5 possible positive zeros.

Is that okay so far?

Answer 2

kinda

Answer 3

3 sign change plus 2 sign change?

Answer 4

wait nvm

Answer 5

Yeah, from left to right, every time a consecutive term has a different sign, I count it. However many sign changes I count is the amount of possible positive solutions.