Question

Write an equation of a line that passes through the point (2, 3) and is parallel to the line y = 2/3 x + 5.

Answer 1

y = -2/3 x
y =-2/3 x − 7
y = 3/2 x
y = 3/2 x + 7

Answer 2

My sis told me u need help

Answer 3

yeah could you help me this question

Answer 4

y = 2
3x + 5

Is this the equation of the line?

Answer 5

i do not know

Answer 6

What is the first equation the question gives you : )
Sorry, it is a bit hard to interpret your question ><

Answer 7

Write an equation of a line that passes through the point (2, 3) and is parallel to the line y = 2/3 x + 5. this is the question so i think the first equation would be y=2/3x+5

Answer 8

Okay, so your previous working out, involves making y the subject, is correct
notice how the coefficient in front of x is the gradient

Answer 9

So from:
y = 3/2 x + 7

m = 3 /2
With this passing through the point (2,3)
remember your point-gradient formula
y - y1 = m (x -x1)

Answer 10

what is y and what is x?

Answer 11

wait is the answer y+3/2 x + 7?

Answer 12

x1 and y1 are from your point (2,1)
where 2 represents the x value and 1 is the y value

Answer 13

I haven't worked it out, give me a moment

Answer 14

to revise : Basic Straight Lines http://openstudy.com/study#/updates/554cca3ee4b075612122616a
go to the above link :)

Answer 15

I got
y = 3x - 4
2

Answer 16

A: y = -2/3 x
B:y =-2/3 x − 7
C:y = 3/2 x
D:y = 3/2 x + 7
these are the answer choices

Answer 17

I think we may have misinterpreted out gradient value of 3/2, I rechecked it again an i got 2/3

through working out, my outcome was:
y = 2x -1
3

Answer 18

thank you

Answer 19

Alright no worries