Can you help me... I WILL GIVE MEDALS!!! What is the equation of the graphed linear model? y = x +
Remember that the equation of a linear function is: y = mx + b Where m is the slope of the line and b is the y-intercept.
b is easiest to solve here, it's the y-value where the line crosses the y-axis. In other words, it's the y-value of x=0.
Is the slope-2?
The slope of the line is equal to the rise and run between two points. I will choose two points: (0, 110) and (20, 70). The rise is: 70 - 110 = -40. The run is: 20 - 0 = 20. Rise/Run gets us: -40/20 = -2. So you are correct.
Are you able to complete the linear equation from here?
is it y=x+(-2)?
Sorry, but that is not correct. y = mx + b Simply substitute the variable m for your numeric slope value and replace b with the y-intercept :)
So, y = -2x + b
Can you tell me what b is?
I got -50
The y-intercept is where the line crosses the y-axis. Can you see that the line crosses the y-axis at y=110?
yes
Using this information, are you able to complete the equation?
idk can u help me more?
Sure. Can you tell me what is confusing you?
Well I must be doing something very wrong... I keep getting -50.
For b
@IParke ?
Sorry about that. Are you solving for b algebraically? The y-intercept (b) is the value of y when x=0. Since we've already found the slope, we have the equation: y = -2x + b, correct? So what is y equal to when our x = 0?
?. Sorry I'm blanking. Can I get another hint?
R u there?
|dw:1433907329394:dw|
|dw:1433907399077:dw|
Join our real-time social learning platform and learn together with your friends!