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The sum of three integers is 92. The second number is three times the first number. The third number is ten less than twice the first number. Find the integers.
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a, b, and c are our 3 integers. Can you make equations using a, b, and c using what you were given in your question?
A + B + C = 92
B= A(3)
C= (A-10) * 2
Now substitue the 2 last equations into the first one :)
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A + (A(3)) + ((A - 10)(2)) = 92
i think the equation for c is close, but not correct
c = 2a - 10 i think
I am not sure
but yeah after you fix that and plug it in, you just solve for A
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Yes, c = 2a -10 is correct. Solve for a, then you can solve for b and c by using the last 2 equations.
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