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Mathematics 15 Online
OpenStudy (anonymous):

Can someone tell me if this answer is correct or not?

OpenStudy (anonymous):

What are the factors of x2 - 81? I put prime

OpenStudy (nikato):

IM BACK! haha and no, its not prime.

OpenStudy (nikato):

its a special kind called difference of square. see how 81 is a perfect square because 9^2=81

OpenStudy (anonymous):

Ah, okay, so would the answer be (x-9) (x-9) then?

OpenStudy (nikato):

(x-9)(x+9) remember with difference of squares theres is one - and the other is +

OpenStudy (nikato):

and you can check. (x-9)(x-9)= x^2 -18x+81

OpenStudy (anonymous):

I did (x-9)(x+9) and that didn't work for me. Are you sure? I got x^2-9x+9x-81 After this point I had to either add the -9 to itself and positive 9 or the other way around which wouldn't equal x^2=-81

OpenStudy (pawanyadav):

x^2-y^2= (x+y)(x-y) always. In your question y=9.

OpenStudy (anonymous):

Wait so do you always have to cross out the two x that isn't squared or cubed?

OpenStudy (nikato):

ys. because they cancel each other. they add up to 0

OpenStudy (nikato):

well, only in this problem

OpenStudy (anonymous):

Ooooh, okay. That makes allot more sense now. Haha, thanks for telling me.

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