Question

@Miss.SweetiePie

Answer 1

Hey so I'll go over the question we did previously, this one: Triangle FGH, FH = 7 ft, FG = 12 ft, F = 70 degrees, I forgot the other one so if you need help on any other just post here but I'll do this one right now and you can go over it.

Answer 2

so angle G is what we need to find, so here we'll have to use cosine rule twice.

Answer 3

\[a^2=b^2+c^2-2bccos(A)\] so this is the cosine rule, so the way we can apply this is if we have two sides and angle between them, so in our case we'll find f first.
\[f^2=g^2+h^2-2gh(\cos(f)) \implies f^2 = 7^2+12^2-2(7)(12)\cos(70)\]
\[f^2 = 135.54 \implies f = \sqrt{135.54} = 11.64\] so side f is 11.64 ft