Question

:)

Answer 1

uhhhhhhhhh we can just plug in those values and solve?!!!

Answer 2

YA I KNOW BUT EVERY TIME I MESS UP -_- AND I NEED HELP PLEASE!

Answer 3

\[2r^2+3s^3-r^2+4t^2-r^2\]
\[-3a^2-b^3+3c^2-2b^3\]

Answer 4

19
http://www.mathpapa.com/algebra-calculator.html

Answer 5

well ok.. we can combine like terms first to make it easier
\[2r^2-r^2-r^2+3s^3+4t^2\]
\[2r^2-2r^2+3s^3+4t^2\]
\[3s^3+4t^2\]

s=-3

t=5

\[3(-3)^3+4(5)^2\]
\[3(-27)+4(25)\]
\[-81+100=19\]

Answer 6

yup checks out on the first one I got 19 too, but at least I showed work :P

Answer 7

The second question too i am confused on can you help with that too?

Answer 8

Find −3a2 − b3 + 3c2 − 2b3 if a = 2, b = −1, and c = 3.

Answer 9

\[-3a^2-3b^3+3c^2\]
a=2, b=-1, c = 3
\[-3(2)^2-3(-1)^3+3(3)^2\]
\[-3(4)-3(-1)+3(9)\]
\[-12+3+27 =18\]

Answer 10

Thank you!

Answer 11

Thank who?

Answer 12

I would thank the creator of the algebra calculator.

Answer 13

^which you shouldn't depend on.. because that's not really learning how to solve these problems.

Answer 14

It shows you the steps!

Answer 15

True, but if OP has a closed book closed note test... then what? The only way to solve it is the manual way.

Answer 16

these sites that automatically solve the problem for you are only supposed to be used to check your answer... it shouldn't be a replacement to do the math the pencil and paper way.

Answer 17

@cutiiepie7272 you must learn to replace each variable with a given value and simplify the resulting numerical expression.

Answer 18

Any questions?

Answer 19

This is called the substitution principle:

An expression maybe replaced by another expression that has the same value.

Answer 20

4 + 2 can be replaced by 6 because they have the same value
4 + 2 = 6.

Similarly, if x = 6, then x can be replaced by 6 because they have the same value
6 = 6.

Answer 21

Also, please use the "^" symbol for exponentiation :-)