Question

Simplify secθ + secθtan^2θ.

A.) 1
B.) cosθ
C.) secθ
D.) sec^3θ

Answer 1

factor!

Answer 2

example please.

Answer 3

sec theta = x
tan theta = y
so you can write it as \[\huge\rm (x+xy^2)\]
so what is common in these both terms ?

Answer 4

x

Answer 5

yes right so take it out\[\huge\rm x(1+y^2)\]
now you can replace x and y
by sec an tan \[\huge\rm sec \theta (1+ \tan^2)\]
1+tan^2 = what ?
^^^^identity

Answer 6

i still dont understand whatsoever.

Answer 7

it's same like simple algebra
first we have to find GCF(greatest common factor)
\[\huge\rm sec \theta + \sec \theta \tan^2 \]
sec is common so take it out
and divide both terms by common factor write your answer in the parentheses
\[\sec \theta (1+ tan^2 \theta )\]