Simplify completely quantity 5 x squared plus 9 x minus 2 over quantity x squared plus 12 x plus 20 times quantity x squared plus 17 x plus 70 over quantity 15 x minus 3.
Is this correct? \[\frac{ 5x^2 + 9x - 2 }{ x^2 + 12x + 20 } \times \frac{ x^2 + 17x + 70 }{ 15x - 3 }\]
Yes
Try factorising each part of the expression, you'll find some factors on the top and bottom of the fraction that cancel out.
Ok I did but I think im doing something wrong
What did you get when you factorised it all?
\[5x2+9x-2 \] \[(x+2) (x+10)\]
\[(x+10) ( x+7)\] \[3(5x)\]
The first one can be factorised, so you get \[5x^2 + 9x - 2 = (5x-1)(x+2)\] and you forgot a term on the denominator of the 2nd bit, you should get \[3(5x-1)\] instead of \[3(5x)\] When you change that, you should get a bunch of cancellation :)
so my answer should be (x+7) over 3
Correct :)
Thank you
No problem!
This is correct! The answer was A) (x+7)/3
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