A bag has 1 red marble, 4 blue marbles, and 3 green marbles. Peter draws a marble randomly from the bag, replaces it, and then draws another marble randomly. What is the probability of drawing 2 blue marbles in a row? Explain your answer.
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OpenStudy (misty1212):
HI!!
OpenStudy (misty1212):
you got a clue or you want to go real slow?
OpenStudy (anonymous):
hi again lol
OpenStudy (anonymous):
I kinda have a clue but im not sure
OpenStudy (misty1212):
ok so lets take it step by step
how many marbles are in the bag total?
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OpenStudy (anonymous):
8
OpenStudy (misty1212):
ok and how many are blue?
OpenStudy (anonymous):
4
OpenStudy (misty1212):
ok good, so what is the probability that the first one selected is blue?
OpenStudy (anonymous):
ummm
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OpenStudy (anonymous):
4/8?
OpenStudy (misty1212):
make a guess, if you are wrong i will tell you
OpenStudy (misty1212):
yeah
\[\frac{4}{8}\] except that you really want to say \(\frac{1}{2}\) same thing
OpenStudy (anonymous):
oh ok
OpenStudy (misty1212):
now you put the marble back (it says that) so you still have 4 blue marbles in the bag and 8 total
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OpenStudy (anonymous):
oh so it would be 1/2 again?
OpenStudy (misty1212):
yes
and for them both to happen, blue and then blue again, the probability is the product of those two
OpenStudy (misty1212):
i.e.
\[\frac{1}{2}\times \frac{1}{2}\]
OpenStudy (misty1212):
hope that is more or less clear
OpenStudy (anonymous):
Yeah makes sense
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