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Use the discriminant to determine the number if real roots for the quadratic equation. y=x^2 -10x + 25 A. one real root B. two real roots C. no real roots d. no solution to the equation My answer: A but can you show me how I go the answer
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sure \[x^2-10x+25=(x-5)^2\]
thanks for ur help I really do accept it
and i have more question that I need to help on and to tell me if I am right or wrong
actually it says "use the discriminant" if you compute \[b^2-4ac\] you will get \(0\) so one solution, but if the discriminant is zero, then you have a prefect square so same thing
oaky thanks
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