Question

(4a4 − 27a3 + 53a2 − 42a + 24) ÷ (a2 − 6a + 8)

Answer 1

Plz factorise
a^2-6a+8

Answer 2

Agsin factorise
4a^4-27a^3+53a^2-42a+24

Answer 3

(a-4)(a-2)

Answer 4

Right

Answer 5

(4a^2 - 3a + 3) (a - 2) (a - 4)

Answer 6

Now just cancell out frm numerator n denominator

Answer 7

so the answer would be 4a^2-3a+3 ?

Answer 8

Wt u will get after cancellation

Answer 9

Correct!!!!

Answer 10

Thanks!!

Answer 11

U r most welcome!!

Answer 12

I am wondering if this problem is really just use factoring to cancel out like terms. Or solve this equation using long division.

Answer 13

I haven't tried to solve it myself, but if the numerator can be factored nicely, it would yield the same result. I have to leave shortly but I can try and work through it before I do

Answer 14

@UsukiDoll I got the same answer by long division. @shamim 's method seems absolutely fine to me

Answer 15

ok...it's probably because I wasn't taught that method which I wondered why that was valid.