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Mathematics 28 Online
OpenStudy (anonymous):

Evaluate. http://static.k12.com/bank_packages/files/media/mathml_3ad92e4b86aec91607782447dc174d5c7d8ad588_1.gif A.http://static.k12.com/bank_packages/files/media/mathml_fc441d195065d3b202d3eac27906a797cab21998_1.gif B.http://static.k12.com/bank_packages/files/media/mathml_6c3c363be32e97e4c70cd484f23f720bfaffde67_1.gif C.http://static.k12.com/bank_packages/files/media/mathml_0dce1350aefb540a05cdf47b2d6ae29e90ccced1_1.gif D.http://static.k12.com/bank_packages/files/media/mathml_1f82c3ef0ef269487a18a198c515407e55a16859_1.gif

OpenStudy (anonymous):

ur in k12 2?

OpenStudy (usukidoll):

need to do the operations in the bracket first.

OpenStudy (usukidoll):

\[-4.5[2x-(0.5-1.4)]\]

OpenStudy (usukidoll):

so taking the bracket first.. we noticed that there is a parenthesis so we need to compute 0.5-1.4 first

OpenStudy (astrophysics):

Yes, this is a question of knowing PEDMAS/ BEDMAS, what ever the kids call it these days.

OpenStudy (usukidoll):

US education system uses PEMDAS but often forget that when there is [ () ] the bracket is taken first into consideration and then do the problem in (I)

OpenStudy (astrophysics):

Right :)

OpenStudy (usukidoll):

I'm just waiting for the OP to respond to what's 0.5-1.4

OpenStudy (usukidoll):

I don't want to be one of those people with A is the answer or 1239 here's the link to an online calculator.

OpenStudy (astrophysics):

Yes, I see, you're a good teacher!

OpenStudy (usukidoll):

thanks :). I caught someone using an algebra calculator and citing it as the source of the answer.

OpenStudy (astrophysics):

By the way, PEDMAS stands for P = parenthesis E = exponents D = division M = multiplication A = addition S = subtraction Going in that order for the operation :P, just a little note if OP doesn't know haha.

OpenStudy (usukidoll):

B -> bracket.

OpenStudy (astrophysics):

\[\huge \checkmark\]

OpenStudy (anonymous):

so what is it or r u guys helping me solve it

OpenStudy (usukidoll):

we're helping you solve it \[-4.5[2x-(0.5-1.4)] \] we consider the bracket first then since there is a () and P is present we need to solve 0.5-1.4

OpenStudy (astrophysics):

Sorry to intrude like that Usuki, I will let you continue, good luck :)

OpenStudy (usukidoll):

so what is 0.5-1.4 ?

OpenStudy (anonymous):

-0.9

OpenStudy (usukidoll):

yes

OpenStudy (usukidoll):

\[-4.5[2x-(-0.9)]\]

OpenStudy (usukidoll):

now we need to distribute the negative so -0.9 becomes positive

OpenStudy (usukidoll):

\[-4.5[2x+0.9]\] we can't combine 2x and 0.9 because x is a variable and we have a constant (a number) so we can go ahead and distribute the -4.5 throughout the whole equation

OpenStudy (usukidoll):

so what is -4.5(2x) same as -4.5 times 2x and -4.5 x 0.9

OpenStudy (usukidoll):

you just have to compute -4.5 x 0.9 and -4.5(2x)

OpenStudy (usukidoll):

and then by doing those computations... this is the answer -9x-4.05

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