Question

How many liters of 10% salt solution must be added to 20% salt solution in order to obtain 10 liters of 12% salt solution?

Answer 1

Say we need to add \(x\) liters of 10% salt solution,
then the amount of 20% salt solution would be \(10-x\) as we want 10 liters

Answer 2

salt in \(x\) liters of 10% solution = \(0.1x\)

salt in \(10-x\) liters of 20% solution = \(0.2(10-x)\)

Answer 3

Since we want the final solution to have 12% salt, add the previous expressions and set it equal to \(0.12(10)\) :

\[0.1x +0.2(10-x) ~=~0.12(10) \]

solve \(x\)

Answer 4

oh it's 8 liters? am i right?

Answer 5

Correct!

Answer 6

Thank you :D

Answer 7

yw:)