NEED HELP FAST! I WILL GIVE MEDAL AND FAN!! Write the equation of the line that is parallel to the line 3x - y = -3 and passes through the point (4, -2).
what have you tried? :)
could you find the slope of 3x - y = -3 ?
Slope of line must be 3. y=3x+3 Comparwith y=mx+c
Let eq be y=3x+c Find c by satisfying the equation with (4,-2) Then put value of c in above equation you will get the answer.
Slope of line must be 3. y=3x+3 Comparwith y=mx+c
So i have to change the equation to y=mx+b?
Yes
so it would be y=3x-3?
Y=3x+3
in the answer choices they're looking for a fraction in the equation
you got how the slope is 3 ?
yes i get that part
becaus b= slope in y=mx+b
yes, so your answer will be of the form y - 3x +c now we have the point 4,-2 plug in x= 4, y= -2 in that
in y= 3x+c **
No m is the slope .
-2 = 3*4 + c
b is the point where the line cuts the y-axis
yes the y-intercept sorry i got confused for a second i realize that now thank you
-2 = 3*4 + c yes thats right, now what is c ?
3?
Welcome, now solve other part carefully.
how? -2 = 12 +c subtract 12 from both sides to get c
-14 = c
-2 =3*4 -14
yes, so your equation as of now is y = 3x -14 right ? now what are your choices?
no right now i have -2 = 3*4 - 14
we had y = mx +c the slope we got , m = 3 so we were y= 3x +c. now we need to just find the "c" part. for which we used the given point. and got c = -14
and if we plug c in y = 3x+c, we get y = 3x -14 :)
yes! but the answer choiches all have fractions in them
nevermind
that is correct thanks so much for your help!
most welcome ^_^ hallp to help :)
*happy
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