Question

!!!

Answer 1

here is a simple method

in a quadratic \[y = ax^2 + bx + c\]

the line of symmetry is found using

\[x = \frac{-b}{2a}\]

so in your question a = 3 and b = 6

so find the line of symmetry

now the vertex always lies on the line of symmetry, so substitute you answer into the equation to find the value of y.

Answer 2

the alternative is to factor out 3

\[y = 3(x^2 + 2x + 1) \]

now factor

Answer 3

Coordinates are (-b/2a,-d/4a)
b=6
a=3
d=b^2-4ac=6^2-4×3×6=-36
Now put values in coordinates of vertax

Answer 4

I did