Question

What is the equation of the line that passes through (4, -1) and (-2, 3)?
a) 2x-3y-5=0
b) 2x+3y-5=0
c) -2x+3y-5=0

Answer 1

We need to find the slope first so we need to use the slope formula
\[\huge~\rm~\frac{ y_2-y_1 }{ x_2-x_1 }\]

Answer 2

y-y1={y2-y1} /(x2-x1) ×(x-x1)

Answer 3

I got 1/3 for the slope formula, is that right?? @pooja195

Answer 4

i was thinking 1 .. ...

Answer 5

3-1=2
-2+4=2
2/2=1

Answer 6

Put y2=3
Y1=-1
x2=-2
x1=4

Answer 7

???

Answer 8

i did the formula wrong... i got it now

Answer 9

no

Answer 10

my bad
3+1=4
-2+4=2
4/2=2 :/

Answer 11

So we are going to use the slope formula first so \[\large \frac{-1+(-3)}{4-(-2)}\]