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Mathematics 17 Online
OpenStudy (anonymous):

Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.) f(x) = 6x^3 + x^2 + 6x Please help!

OpenStudy (anonymous):

Critical numbers are where the derivative is 0. What did you get for f'(x)?

OpenStudy (anonymous):

18x^2+2x+6

OpenStudy (anonymous):

ok. so you want to solve 18x^2+2x+6 = 0 using the quadratic formula or some other method

OpenStudy (anonymous):

oh okay!

OpenStudy (anonymous):

i got 4+-sqroot(-428)/36

OpenStudy (anonymous):

Ok, so √-428 is an imaginary number, so there are no values of x where the derivative is 0, which means there are no critical values.

OpenStudy (anonymous):

so my answer would be DNE

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

thank you!!

OpenStudy (anonymous):

you're welcome!

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