Question

CHECK MY WORK!!
The length of a rectangle is 24 units. Can the perimeter x of the rectangle be 60 units when its width y is 11 units?

No, the rectangle cannot have x = 60 and y = 11 because x = 48 + 2y
No, the rectangle cannot have x = 60 and y = 11 because x = 24 + 2y
Yes, the rectangle can have x = 60 and y = 11 because x + y is greater than 48
Yes, the rectangle can have x = 60 and y = 11 because x + y is greater than 24
I know that it is a or b, right?

Answer 1

hint:

perimeter (P)

P = 2*L + 2*W

L = length
W = width

Answer 2

a??

Answer 3

@jim_thompson5910 a?

Answer 4

yes

P = x
L = 24
W = y

P = 2*L + 2*W
x = 2*24 + 2*y
x = 48 + 2y

Answer 5

you'll find that if L = 24 and W = 11, then the perimeter is actually 70 (not 60)

Answer 6

thanks

Answer 7

yw