Which polynomial identity will prove that 65 = 81 - 16?

Binomial Multiplication
Difference of Cubes
Sum of Cubes
Difference of Squares

Question

Which polynomial identity will prove that 65 = 81 - 16?

 Binomial Multiplication
 Difference of Cubes
 Sum of Cubes
 Difference of Squares

anonymous · Answer

B

anonymous · Answer

Why?

anonymous · Answer

81 = 9^2 
hint2 : 16 = 4^2

65 = 81-16 = 8^2 - 4^2 = (9+4)(9-4) = (13)(6) = 65

akashdeepdeb · Answer

It's not B.

What do you think the answer should be and why?
Try to reason, logically.

anonymous · Answer

I have no idea because none of those numbers are squared or cubed but theyre being subtracted so I would go with the difference of. So B or D

akashdeepdeb · Answer

Yes, the answer is D.
This is because 81 and 16 are perfect squares. 
That means, 
$9^2 = 81$
$4^2 = 16$
$65 = 81 - 16 = 9^2 - 4^2 = difference ~~of~~ perfect ~~squares = D$