Ask your own question, for FREE!
Mathematics 16 Online
OpenStudy (anonymous):

What is the perimeter of the figure to the nearest hundredth of an inch? A. 68.24 inches B. 43.12 inches C. 38.56 inches D. 26 inches

OpenStudy (anonymous):

@Deadpool117 can you help me bugaboo??

OpenStudy (anonymous):

yes one second

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

\[9+8+9+\frac{2* \pi*4 }{ 2 }=?\]

OpenStudy (anonymous):

ok he beat me..

OpenStudy (anonymous):

3.14 i think idk tho??

OpenStudy (anonymous):

\[26+4 \pi=26+4*3.14=26+12.56=38.56=?\]

OpenStudy (anonymous):

okay im sorry i dont get any of this lol sorry

OpenStudy (anonymous):

its B, Babygurl ^-^

OpenStudy (anonymous):

circumference of a circle=2*pi*r

OpenStudy (anonymous):

okay thx bugaboo

OpenStudy (anonymous):

no problem

OpenStudy (anonymous):

but it is a semi circle so half of it

OpenStudy (anonymous):

wym..?

OpenStudy (anonymous):

that would make it 26 then?

OpenStudy (anonymous):

diameter=8 radius=8/2=4

OpenStudy (anonymous):

okay im confused

OpenStudy (anonymous):

let me know where are you confused.

OpenStudy (anonymous):

i am confused with everything

OpenStudy (anonymous):

perimeter is the boundary of whole figure

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

so first we add three straight sides

OpenStudy (anonymous):

9+8+9=26

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

circumference of semi circle\[=\frac{ 2 \pi r }{ 2 }=\pi r=3.14*4=12.56\]

OpenStudy (anonymous):

now add

OpenStudy (anonymous):

26+12.56=38.56

OpenStudy (anonymous):

okay so c?

OpenStudy (anonymous):

circumference is also the boundary of circle.

OpenStudy (anonymous):

okay and thx so much

OpenStudy (anonymous):

now you got it.

OpenStudy (anonymous):

yeah i get it now

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!