Ask your own question, for FREE!
Mathematics 22 Online
OpenStudy (anonymous):

A jar contained 18 red marbles, 14 green marbles, and 20 blue marbles. A marble was selected at random, the color was recorded, and the marble was placed back in the jar. The table shows the results after 60 trials. What was the relative frequency of selecting a blue marble? Round to the nearest percent, if necessary. Outcome Red Green Blue Number of trials 22 18 20

OpenStudy (anonymous):

at first when u add them all u have is 52 right? so then u have to think so 60-52 is 8 you would think 8 marbles were selected so that means that 4 reds were added then 4 greens were added but in total 8 were added ..I don't think u have to round anything..hope this helped u @amberosales :)..let me know

OpenStudy (anonymous):

what is the difference between software access restrictions and physical access restrictions

OpenStudy (anonymous):

I have no idea sorry

OpenStudy (sdfgsdfgs):

Total no of trials = 60 Blue trials = 20 Relative frequency for blue = blue/total = 20/60 * 100%

OpenStudy (anonymous):

thx for the medal @amberosales

OpenStudy (anonymous):

So what's the answer? :) @Angelsoft Sorry I got kinda lost.

OpenStudy (anonymous):

so I was thinking cause their were 14 green marbles and 18 what I did is add all of the amount of marbles for each color and I got 52 and then I did 60-52=8 and I relized that red has 22 and green has 18..red and green each have gotten 4 extras ,..so 8

OpenStudy (anonymous):

Ooh, thank you! :)

OpenStudy (anonymous):

Sorry but you got it wrong :( @Angelsoft

OpenStudy (anonymous):

oh im sorry then :(

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!