Mathematics
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OpenStudy (anonymous):
Let f(x) = 3x2 – x + 2 and g(x) = 5x2 – 1. Find f(g(x)).
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OpenStudy (anonymous):
@johnweldon1993
OpenStudy (anonymous):
Will medal AND fan <3
Nnesha (nnesha):
bec you have to substitute x for x you will get same equation so just
substitute g(x) equation into f(x)
OpenStudy (anonymous):
I'm confused
OpenStudy (astrophysics):
\[f(g(x)) = 3(5x^2-1)-(5x^2-1)+2\] notice we take the function g(x) and plug it everywhere there is an x in f(x) which means f(g(x)).
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OpenStudy (astrophysics):
\[f(g(x)) = 3(5x^2-1)^2-(5x^2-1)+2\] this is the proper one
OpenStudy (anonymous):
Ok. I see
OpenStudy (astrophysics):
Now you may simplify it :)
OpenStudy (anonymous):
Can you wait until I finish so you can check my answer? :)
OpenStudy (anonymous):
15x^2-3-5x^2+7 yes?
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OpenStudy (astrophysics):
Mhm, not quite, notice it's \[3(5x^2-1) \huge ^{2}\]
OpenStudy (anonymous):
Ok. I don't understand
OpenStudy (astrophysics):
\[(5x^2-1)^2 \implies (5x^2-1)(5x^2-1)\]
OpenStudy (anonymous):
Ohh! Okay
OpenStudy (astrophysics):
Yup :)
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OpenStudy (anonymous):
25x^4-10x^2+1
OpenStudy (astrophysics):
Awesome, now lets multiply it by 3 \[3(25x^4-10x^2+1)\]
OpenStudy (anonymous):
75x^4-30x^2+3
OpenStudy (astrophysics):
That's great :D, now we have \[75x^4-30x^2+3 -(5x^2-1)+2\]
OpenStudy (astrophysics):
Now simplify it a bit more
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OpenStudy (anonymous):
75x^4-30x^2-5x^2+3
OpenStudy (astrophysics):
Good one more step though, look for like terms
OpenStudy (anonymous):
75x^4-35x^2+3
OpenStudy (astrophysics):
Yup, nice work!!
OpenStudy (anonymous):
Is that it?
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OpenStudy (astrophysics):
Yup, we're done :)
OpenStudy (anonymous):
Can I ask one more please? :)
OpenStudy (astrophysics):
\[f(g(x)) = 75x^4-35x^2+3\]
OpenStudy (astrophysics):
Unless you want solutions to it as well, but I doubt it, since it's gross...and sure :)
OpenStudy (anonymous):
Lol okay thanks :)
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OpenStudy (astrophysics):
And we are solving for x? :)
OpenStudy (anonymous):
Solve the equation for the variable. Show each step of your solution process.
OpenStudy (astrophysics):
Sounds fun, any idea how to start
OpenStudy (anonymous):
And yes :) You know, the usual
OpenStudy (astrophysics):
See if you can do anything with the 4
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OpenStudy (anonymous):
subtract it from 5?
OpenStudy (astrophysics):
Yup
OpenStudy (astrophysics):
|dw:1434493963942:dw| so far so good right