If p varies directly with q, and p = 10 when q = 2, what is the value of p when q = 20?
A.
p = 28
B.
p = 100
C.
p = 1
D.
p = 40
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Nnesha (nnesha):
what 's the equation for direct variation ??
OpenStudy (anonymous):
i dont remember and i suck at it
Nnesha (nnesha):
direct variation y = kx
y varies directly with x :-)
OpenStudy (anonymous):
Well it is just a ratio
OpenStudy (anonymous):
okay yeah i remember that now
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Nnesha (nnesha):
alright so p varies directly with q
write an equation
OpenStudy (anonymous):
Don't you just multiply p•5?
OpenStudy (anonymous):
100?
Nnesha (nnesha):
nope what's the equation p varies directly with q ?
Nnesha (nnesha):
y varies directly with q
y = kx
now replace y by p and x by q
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OpenStudy (anonymous):
whaaaaaa
OpenStudy (anonymous):
\[10=k2\] ?
OpenStudy (anonymous):
?
Nnesha (nnesha):
sorry intnt gt disconnected
Nnesha (nnesha):
that's right solve for k
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OpenStudy (anonymous):
k=5?
Nnesha (nnesha):
right
\[\huge\rm p=2q\]
substitute q value solve for p
OpenStudy (anonymous):
okay so what would it be when its 20?
Nnesha (nnesha):
yes right
OpenStudy (anonymous):
?
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Nnesha (nnesha):
ohh sorry i thought u said q would be 20 .-.
Nnesha (nnesha):
so replace q by 20 solve for p
Nnesha (nnesha):
\(\color{blue}{\text{Originally Posted by}}\) @Nnesha
right
\[\huge\rm p=2q\]
substitute q value solve for p
\(\color{blue}{\text{End of Quote}}\)
q=20 plug in
OpenStudy (anonymous):
40!
OpenStudy (anonymous):
@Nnesha ?
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