Ok I honestly have no clue how to do this please can someone explain to me what I have to do?
Choose the equation below that represents the line passing through the point (-3, -1) with a slope of 4.
y-1=4(x-3)
y+1=4(x+3)
y-3=4(x+1)
y+3=4(x-1)

Question

Ok I honestly have no clue how to do this please can someone explain to me what I have to do?
Choose the equation below that represents the line passing through the point (-3, -1) with a slope of 4.
y-1=4(x-3)
y+1=4(x+3)
y-3=4(x+1)
y+3=4(x-1)

pooja195 · Answer

$$\huge~\rm~y-y_1=m(x-x_1)$$
(x1,y1)
m=slope 
plug in the info

anonymous · Answer

y-3=4(x+1)?

pooja195 · Answer

you have your X and Y values mixed up
$\huge\color{red}{(x_1,y_1)}$

anonymous · Answer

I have -3 as x and -1 as y?
ohh wait I see what you mean now it should be 
y-1=4(x-3)?

anonymous · Answer

would the 1 also become positive ?

pooja195 · Answer

$\huge~\color{red}{y+1=4(x+3) }$

anonymous · Answer

oh ok i get it 
Thank you sooo much!

anonymous · Answer

ok this is another one I have no clue how to do .....well I think I just dont know what format to use
If f(x) = 2x2 - 30, find f(4).

pooja195 · Answer

repost that :) also you are welcome!
$\huge\color{orange}{Welcome~To~OpenStudy!!~:)}$

anonymous · Answer

ok this is another one I have no clue how to do .....well I think I just dont know what format to use
If f(x) = 2x2 - 30, find f(4).

pooja195 · Answer

On a difrent post meaning close this and post again

anonymous · Answer

ohh ok