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Mathematics 20 Online
OpenStudy (anonymous):

Help please????? What is the equation of the following graph? THANK YOU <3

OpenStudy (anonymous):

OpenStudy (jack1):

so... where would you start with this?

OpenStudy (anonymous):

I'm not really sure. I'm not really good at the section I'm currently doing.

OpenStudy (jack1):

that's ok so with a normal parabola (like the below) do you knopw how to get the equation of the line into a form like y = ax^2 + bx + c |dw:1434614183620:dw| (lets pretend thats a curve and my touchpad isn't being moody) ;)

OpenStudy (anonymous):

I think so

OpenStudy (anonymous):

it s a hyperpola

OpenStudy (anonymous):

to determinat the exact equation you have to know the hyperbola formula ; and then compare it to the graph

OpenStudy (anonymous):

Can you help me do that please?

OpenStudy (jack1):

sorry my modems being ... interesting...

OpenStudy (jack1):

sorry general form of this type of equation is (x^2/a^2) - (y^2/b^2) = 1

OpenStudy (anonymous):

how do I get a and b?

OpenStudy (anonymous):

this should help you out http://bosscade.com/c?r=CKUEDE4sd

OpenStudy (anonymous):

@thesn1 can u confirm this link? http://bosscade.com/c?r=CKUEDE4sd

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