In ∆ABC, if a = 8.75 centimeters, c = 4.26 centimeters, and m B = 87°, what is the length of b to two decimal places?
A)8.92 CM B)9.41CM C)9.53CM D)13.01 E)15.36
you will need the law of cosines to solve it b2=a2+c2−2a×c×cos(B) just substitute your values
Solution: cosB= (a^2+c^2-b^2)/2ac b = sqrt(a^2+c^2-2ac*cosB) = sqrt(8.75^2+4.26^2-2*8.75*4.26*cos87) =9.53 So b=9.53cm
my teacher hasn't taught us that yet and shes giving us stuff to do can you walk me through
Really? how does she expect you to solve it if you don't know "sohcahtoa" What grade are you in?
I don't know , ima a sophomore
Hmmm, sorry i'm a freshman. Is this for geometry?
yes
That's weird :/ I learned sohcahtoa in my freshman year, (I'm going to be a sophomore in the upcoming year). I don't know how to help you but goodluck!
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