Question

Write an indirect proof to show that the diagonals of a parallelogram bisect one another.

Answer 1

I need to check my answer!

Answer 2

Let's assume that the diagonals of a parallelogram do not bisect one another. A parallelogram has four sides and it's opposite angles and sides are congruent and parallel. If it's opposite sides are parallel and congruent, and so are it's angles, then the diagonals of a parallelogram must intersect each other.

Answer 3

@Abhisar @ganeshie8

Answer 4

@Whitemonsterbunny17

Answer 5

Seems that here you are proving that they intersect and not that they bisect

Answer 6

What's the difference between intersection and bisection?

Answer 7

I thought they were the same. :/

Answer 8

so intersection is that two lines meet at the same point
bisection is that they meet at the same point AND this point splits them in two equal segments

Answer 9

Wait, I think I remember, bisection means they cut eachothe rin halves

Answer 10

Ahh, okay! I forgot completely.

Answer 11

But the start of your proof seemed reasonable, you should elaborate further

Answer 12

Remind: Should state that parallelogram is not a reflex quadrilateral, hence their diagonals intersect.

Answer 13

Thank you, I'm understanding better now. But do you think you could give me a hint to get started on when else I should be writing, please?

Answer 14

Is this one okay?

Let's assume that the diagonals of a parallelogram do not bisect one another. A parallelogram has four sides and it's opposite angles and opposite sides are congruent and parallel. If the diagonals of a parallelogram intersect each other, and a parallelogram's opposite angles and opposite sides are congruent and parallel, then the intersecting diagonals must also be bisecting one another.

Answer 15

@Abhisar