A metal rod is placed in a rectangular box as shown in the figure.
How long is the rod? Round your answer to the nearest tenth of an inch, if necessary.
A.
5.0 in.
B.
12.1 in.
C.
13.4 in.
D.
14.2 in.
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OpenStudy (anonymous):
@xapproachesinfinity
OpenStudy (anonymous):
Image
OpenStudy (xapproachesinfinity):
first we begin by finding the length of the diagonal of the bottom rectangle
we use Pythagoras again
that diagonal is a hypethenus if you can see it
OpenStudy (anonymous):
ok
OpenStudy (xapproachesinfinity):
so heypethenus = sqrt{3^2+4^2}=sqrt{9+16}=sqrt{25}=5 inch
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OpenStudy (xapproachesinfinity):
now we look at the triangle from by the the metal rod
we have the long side is 11 inch and the short one we just found is 5
the rod is like a hypotenuse in that triangle
so the length of the rod = sqrt{5^2+11^2}=sqrt{25+121}=sqrt{146}
OpenStudy (xapproachesinfinity):
to the nearest 10th
it is 12.08 inch
OpenStudy (xapproachesinfinity):
you got it ?
OpenStudy (anonymous):
is that the answer?
OpenStudy (anonymous):
wouldn't it be 12.1?
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OpenStudy (xapproachesinfinity):
nearest tenth you look at two digits after decimal
OpenStudy (anonymous):
did you see the answer choices? It also says tenth if an inch.
OpenStudy (xapproachesinfinity):
i'm sorry it should be one digit after decimal
fasting effects haha
OpenStudy (xapproachesinfinity):
so you are correct
OpenStudy (anonymous):
so it is 12.1
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OpenStudy (xapproachesinfinity):
yes
OpenStudy (anonymous):
ok next?
OpenStudy (xapproachesinfinity):
ok go ahead!
next i will give some time to do some of it
and see where exactly you stuck
OpenStudy (xapproachesinfinity):
is that ok
OpenStudy (anonymous):
sure.
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