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Mathematics 8 Online
OpenStudy (anonymous):

A metal rod is placed in a rectangular box as shown in the figure. How long is the rod? Round your answer to the nearest tenth of an inch, if necessary. A. 5.0 in. B. 12.1 in. C. 13.4 in. D. 14.2 in.

OpenStudy (anonymous):

@xapproachesinfinity

OpenStudy (anonymous):

Image

OpenStudy (xapproachesinfinity):

first we begin by finding the length of the diagonal of the bottom rectangle we use Pythagoras again that diagonal is a hypethenus if you can see it

OpenStudy (anonymous):

ok

OpenStudy (xapproachesinfinity):

so heypethenus = sqrt{3^2+4^2}=sqrt{9+16}=sqrt{25}=5 inch

OpenStudy (xapproachesinfinity):

now we look at the triangle from by the the metal rod we have the long side is 11 inch and the short one we just found is 5 the rod is like a hypotenuse in that triangle so the length of the rod = sqrt{5^2+11^2}=sqrt{25+121}=sqrt{146}

OpenStudy (xapproachesinfinity):

to the nearest 10th it is 12.08 inch

OpenStudy (xapproachesinfinity):

you got it ?

OpenStudy (anonymous):

is that the answer?

OpenStudy (anonymous):

wouldn't it be 12.1?

OpenStudy (xapproachesinfinity):

nearest tenth you look at two digits after decimal

OpenStudy (anonymous):

did you see the answer choices? It also says tenth if an inch.

OpenStudy (xapproachesinfinity):

i'm sorry it should be one digit after decimal fasting effects haha

OpenStudy (xapproachesinfinity):

so you are correct

OpenStudy (anonymous):

so it is 12.1

OpenStudy (xapproachesinfinity):

yes

OpenStudy (anonymous):

ok next?

OpenStudy (xapproachesinfinity):

ok go ahead! next i will give some time to do some of it and see where exactly you stuck

OpenStudy (xapproachesinfinity):

is that ok

OpenStudy (anonymous):

sure.

OpenStudy (xapproachesinfinity):

ok then post :)

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