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I will give a medal. Please explain how to do it not just the answer, thanks! Solve x^2 - 3x = -8.
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HI!!
Hello.
add 8 and solve \[x^2-3x+8=0\] using the quadratic formula \[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] with \[a=1,b=-3,c=8\] there will be no real solutions, but two complex ones
So would \[x=3+-i \sqrt{23}/2\] be correct?
@misty1212
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yes, but the real part is 3/2, not just 3
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