Part A: Divide (8x4y3 + 4x3y2 - 2x2y - 12x2y4) by -2x2y. Show your work, and justify each step. (6 points)

Part B: How would your answer in Part A be affected if the x2 variable in the denominator was just an x? (2 points)

Part C: What is the degree and classification of the polynomial you got in Part A? (2 points)

Question

Part A: Divide (8x4y3 + 4x3y2 - 2x2y - 12x2y4) by -2x2y. Show your work, and justify each step. (6 points)

Part B: How would your answer in Part A be affected if the x2 variable in the denominator was just an x? (2 points)

Part C: What is the degree and classification of the polynomial you got in Part A? (2 points)

anonymous · Answer

$$\frac{ 8x4y^3+4x3y^2-2x2y-12x2y^4}{ -2x2y}$$
Do you know what to do here?

oregonduck · Answer

yes you have to divide it

oregonduck · Answer

i just do not know how to divide something so big

oregonduck · Answer

can you plz help

oregonduck · Answer

@LegendarySadist @mathmate @welshfella

oregonduck · Answer

yes i guess so

oregonduck · Answer

@Aureyliant

anonymous · Answer

It's actually quite simple. 
Start with the first part they give you and and divide it by -2x2y
So that gives you:
$$\frac{ 8x4y^3 }{ -2x2y }$$
So 8x/-2x, would be -4.
Now 4y^3/2y would be 2y^2. 
Then you would have to multiply -4(2y^2), giving you -8y^2 for the first part

anonymous · Answer

Do you understand how I got that for the first part of the equation?

oregonduck · Answer

yes

anonymous · Answer

Okay, now do the same for every other part of the equation

oregonduck · Answer

OH MY GOD PEOPLE USE TO GIVE THE ANSWERS NOW THEY ARE ONLY HELPING YOU I AM RUNNING AGAINST THE CLOCK

oregonduck · Answer

NOW ONE HAS HELPED ME FOR 2 HOURS NOW MY QUIZ IS GOING TO LOSE ALL THE INFO

anonymous · Answer

ALRIGHT SASSY. 
$$6y^3-8y^2-3y$$ is your answer