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To solve the equation 3sin(2x) = 5cosx, you should rewrite it as____. A. 3sinx + 5cosx = 0 B. cosx(3sinx - 5) = 0 C. cosx(6sinx - 5) = 0
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hint: use eqn sin2A = 2sinAcosA
I am want say A but I have a good feeling it is C
What happens to the 2x if A is the ans?
Oh, now that I look at this way, I see that I don't see how 2x would go into A as the answer. Therefore taking that out of the equation right?
*problem
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correct :)
Awesome! I don't think that B would be the answer because it would have to be '6sinx' instead of '3sinx' right?
also correct :)
Cool! So that would make the answer C!
Thank you for the time and help! I appreciate it!
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welcome - u did most of the work urself! :)
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