Question

Consider a random variable X that takes on the values 0, 1, 2, 3. We specify the function f(x) = -2 + x. Is f(x) a probability mass function?

Answer 1

Is it No because the first and second Kolmogorov axioms are being violated?

Answer 2

no, because f(1)=-1 n first axiom requires P(x) >=0

Answer 3

SO, then it is No because the probabilities do not sum to 1? I just realised the Axiom thing.

Answer 4

do not sum to 1 will be the second axiom but f(x) does not even satisfy the first of being non-negative.

Answer 5

Ok thank you so much!

Answer 6

welcome