How to solve this triangle

C = 114, b = 26, c =21 degrees

When I use Law of Sine

$ \frac{\sin114}{22} = \frac{\sin B}{26} $ I get 1.0796 Am I doing this right?

Question

How to solve this triangle

C = 114, b = 26, c =21  degrees

When I use Law of Sine

$  \frac{\sin114}{22} = \frac{\sin B}{26} $ I get 1.0796  Am I doing this right?

anonymous · Answer

Sorry c = 22

anonymous · Answer

Note, C = 114 degrees and b and c are sides.

jack1 · Answer

i think u have it mixed up?

jack1 · Answer

ah, ok?

abdullahm · Answer

That makes more sense because you put degrees after the little c and that confused it all.

abdullahm · Answer

That doesn't make a triangle though...?

abdullahm · Answer

Are you sure that the numbers you have provided are correct?

jack1 · Answer

usual notation is capital letters are side lengths and small / lower case letters are angles...

anonymous · Answer

Yes the numbers are right. Also, my book has Angles as capital and sides as lower case.

abdullahm · Answer

So to make sure,

you have Angle C = 114 degrees
Side c = 22 units
Side b = 26 units

?

anonymous · Answer

All I did is bump the numders up 1, but my original problem I still get sine being over 1

abdullahm · Answer

Angle C is the largest angle, so it has to have the largest side length, which is not the case. So it can not form a triangle.

anonymous · Answer

AbdullahM that is correct

anonymous · Answer

the origninally problem is  C=113 degres    b =25  and c = 21  but sine is still over 1

abdullahm · Answer

That still doesn't form a triangle, however.

anonymous · Answer

So I take it there is no triangle.

anonymous · Answer

That must be the solution. There is no triangle.

anonymous · Answer

That is what I get.

abdullahm · Answer

That should be the answer as no triangle can be formed with given measurements.

abdullahm · Answer

|dw:1434811264905:dw|

It simply isn't possible.

abdullahm · Answer

If you have any other questions, feel free to tag me :)