Question

solve the equation using quadratic formula.

2x (sqaured) +13x=0

Answer 1

can some one please help ,e i dont get quadratic functions

Answer 2

Find a GCF first do you see any?

Answer 3

13?

Answer 4

It says to solve by using the Quadratic Formula...

What is the Quadratic Formula?

Answer 5

"ax2 + bx + c = 0"

Answer 6

Thats standered form

Answer 7

yeah but for this question thers no c

Answer 8

so that would be 0 then :)

Answer 9

but dont u have tp plug in the numbers? or is it when theres no c then the answer is equivalent to 0?

Answer 10

Name your abc values

Answer 11

a=2 b=13

Answer 12

\[\huge~\rm~ax^2+bx+c=0\]
\[\huge~\rm~2x^2+13x+0=0\]

Answer 13

Now name the abc values

Answer 14

a=2 b=13 c=0?

Answer 15

Great job so far :)

Answer 16

yes! :)
\[\huge~\rm~~x=\frac{ -(13)~\pm \sqrt{(13)^2-4(2)(0)} }{ 2(2)}\]

Answer 17

\[so.... x= -13 \pm \sqrt{169}\]

Answer 18

and then i would subtract 8?

Answer 19

i dont understnd now...

Answer 20

\[\huge~\rm~~x=\frac{ -13~\pm \sqrt{169~x~1} }{ 4}\]
\[\huge~\rm~~x=\frac{ -13~\pm \sqrt{169} }{ 4}\]
Whats the square root of 169?

Answer 21

13

Answer 22

right?

Answer 23

\[\huge~\rm~~x=\frac{ -13~\pm~13 \sqrt{1} }{ 4}\]
now set up two equations and solve
\[\huge~\rm~~x=\frac{ -13~+~13 \sqrt{1} }{ 4}\]
\[\huge~\rm~~x=\frac{ -13~-~13 \sqrt{1} }{ 4}\]

Answer 24

so it would be -13/2 and 0?

Answer 25

those are my two answers correct?

Answer 26

so would i do the same thing for 6x (sqaured) +2x=4?

Answer 27

You would subtract the 4
\[\huge~\rm~6x^2+2x-4=0\]
and go from that