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How would I graph f(x)=27(1.3)x? (It's a exponential function so it has to be a curved line?)
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I made a chart to help me understand but I'm not sure how.. x|f(x) ----- 0|27 1|- 2|- 3|- ---
Would I just do like 27*1.3*2?
well let's fill in the chart
would 1=35.1?
27(1.3) ^1
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oh
so it would be 35.1
Yes
First question...Is itf(x) = 27(1.3)^x or f(x)=27(1.3)x? f(x)=27(1.3)x f(1) = 27(1.3)(1) f(2) = 27(1.3)(2)
then 2 would be 45.63?
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It has to be 27(1.3) ^ x Other wise it's not exponential.
ok
Oh very true!
would 2 be 45.63?
yes
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then 3 would be 59.319?
so then i would plot like (0,27), (1,35.1) (2,45.63) and (3,59.319) with a curved line right?
yes
thank you :)
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