Between what two successive integers does a real zero of P(x) = x3 –2x –5 lie? what are successive integers?
successive integers are integers that follow each other. e.g. 4 and 5 are successive integers, 18 and 19 are successive integers, etc
you can find the zeros of \(P(x)\), and find the integers from that value... for example if you find the real zero to be \(x=1.32\) then you know it lies between \(1\) and \(2\) ---( This is not the solution, i just made up an example ! )
Hey, let \(f(x) = x^3 - 2x - 5\). Notice that \(f(2) = -1\) and \(f(3) = 16\). Therefore a root lies in the interval (2,3).
@Greg_D thanks. so all i have to do is find the zero and did whatever it's between is the answer?
yes! remmeber your answer must be integer numbers!
oh ok. it is between 2 and 3 like parthkohli said. i also must use calculator. Thanks for the help!
Here, I used the Intermediate Value Theorem. There's no real need for a calculator although you can graph the function.
:) you are welcome! @ParthKohli showed a more efficient way to solve this, without finding the value of the zero !
you don't need to actually work out the roots of this equation first.
you need to try successive integers until you observe a sign change - Intermediate Value Theorem as @ParthKohli stated
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