Question

if g(n) =n^2+n and h(n)=n^2-n which of the following is equal to h(m+1)?

g(m), g(m)+1, g(m)-1, h(m)-1

Answer 1

first calculate what h(m+1) evaluates to

Answer 2

m^2+2m+1-m-1 = ,m^2+m

Answer 3

g(m)

Answer 4

why

Answer 5

@wrik003 why is it g(m

Answer 6

because h(m+1) = ((m+1)^2) - (m+1) = (m^2) + m = g(m) (given)... and anyways I don't copy answers without doing the sums! ;-)